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What is the smallest value of sec²θ - 2tan²θ? What is the smallest value of sec²θ - 2tan²θ?
Dear student Sec^2Q – tan^2Q =1 So,the equaton becomes 1 – tan^2Q So minimum value of this equation is 1. Hope this helps Good Luck
Sec^2Q – tan^2Q =1 So,the equaton becomes 1 – tan^2Q hence minimum goes to – infinitywhile maximum is 1
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