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Grade: 12
        
find dy/dx when
y= e^(ax) . sec x . log x/ sqrt(1 – 2x)
5 years ago

Answers : (2)

Rinkoo Gupta
askIITians Faculty
80 Points
							

y= e^(ax) . sec x . log x/ sqrt(1 – 2x)

Taking eaxsecx as first function andlog x/ sqrt(1 – 2x) as second function we use the product rule

dy/dx=eaxsecx.[{√(1-2x).(1/x)-logx.(1/2√(1-2x) )(-2)}/(1-2x)]+

logx/√(1-2x){eaxsecxtanx+secxeax.a}

Now on simplification you get desired result.

Thanks & Regards

Rinkoo Gupta

AskIITians Faculty

5 years ago
Arun Kumar
IIT Delhi
askIITians Faculty
256 Points
							
Hello
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty
5 years ago
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