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find dy/dx wheny= e^(ax) . sec x . log x/ sqrt(1 – 2x)
y= e^(ax) . sec x . log x/ sqrt(1 – 2x)Taking eaxsecx as first function andlog x/ sqrt(1 – 2x) as second function we use the product ruledy/dx=eaxsecx.[{√(1-2x).(1/x)-logx.(1/2√(1-2x) )(-2)}/(1-2x)]+logx/√(1-2x){eaxsecxtanx+secxeax.a}Now on simplification you get desired result.Thanks & RegardsRinkoo GuptaAskIITians Faculty
y= e^(ax) . sec x . log x/ sqrt(1 – 2x)
Taking eaxsecx as first function andlog x/ sqrt(1 – 2x) as second function we use the product rule
dy/dx=eaxsecx.[{√(1-2x).(1/x)-logx.(1/2√(1-2x) )(-2)}/(1-2x)]+
logx/√(1-2x){eaxsecxtanx+secxeax.a}
Now on simplification you get desired result.
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty
HelloThanks & RegardsArun KumarBtech, IIT DelhiAskiitians Faculty
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