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Find the diff eq whose solution represents the family y=ae^3x + be^x
Dear student y = Ae^3x + B e^x Differenciating wrt y we get y1 = 3Ae^3x + Be^x Again differenciating wrt y we get y2 = 9Ae^3x + Be^x The sequence will goes on and there will be no solution.There is problem in the question because there will be no solution to this problemPlease upload the image.
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