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question mark

differentiate the following function with respect to x
(tan x)^1/x

taniska , 11 Years ago
Grade 12
anser 1 Answers
Rinkoo Gupta

y=tanx1/x

taking log on both sides

logy=1/x.logtanx

Now diff. w. r. to x , we get

(1/y) dy/dx=(1/x).(1/tanx).(sec2x)+logtanx(-1/x2)

dy/dx=tanx1/x[1/(xsinxcosx ) – ( logtanx)/x2
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty
Last Activity: 11 Years ago
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