Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Two circles touch each other externally at point p . Apc and bpd are st. Lines. Show that triangle pab and pcd are similar and ab is parallel to cd
Dear Vaibhav The angle between the tangent and any chord at the point of contact is equal to the angle subtended by the arc on the alternate segmenta of the arc.Let T P T' be the tangent.The angle T P A = angle A B D ( through the point of contact P), by reason of above theorem.Similarly, angle T' P C = angle C D B.But angle T P A = angle T' P C as they are opposite angle.Therefore, angle A B D = angle C D B. So the alternate angles are equal, BD being the transversal.This implies AB || CD. RegardsArun (askIITians forum expert)
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -