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The perpendicular from the origin to the line y = mx + c meets it at the point (-1, 2). Find the values of m and c.
The perpendicular from the origin to the line y = mx + c meets it at the point (-1, 2). Find the values of m and c.

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4 months ago

```							Welcome to AskiitiansThe given equation of the line is y = mx + c.From the given condition, the perpendicular from the origin meets the given line at (-1, 2).Hence, the line joining the points (0, 0) and (-1, 2) is perpendicular to the given line.The slope of the line joining (0, 0) and (-1, 2) is= 2/-1 = -2Therefore,m (– 2) = -1 (Since the two lines are perpendicular)m= ½Since points (-1, 2) lies on the given line, it satisfies the equation y = mx + c.Now, substitute the value of m, (x, y) coordinates in the equation:2 = m(-1) + c2 = ½(-1) + c2 = -½ + cC = 2 + (½)C = 5/2Therefore, the value of m and c are ½ and 5/2 respectively.Thanks
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4 months ago
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