1800-150-456-789
FlagBACK
Flag AIPMT> A particle move along the parabolic path ...
question mark

A particle move along the parabolic path x = y²+2y+2 in such a way that the y-component of velocity vector remain 5m/s during the motion. The magnitude of the acceleration of the particle is

Abhishek Dogra , 6 Years ago
Grade 11
anser 1 Answers
Susmita

Last Activity: 6 Years ago

x=y2+2y+2
Differentiate with respect  to time t to obtain velocity components along x and y direction respectively.
vx=2yvy+2vy
where vx=dx/dt and vy=dy/dt.
Given vy=5m/s.
So vx=10y+10
Differentiate  again with respect  to  time  t  to  obtain  acceleration.
ax=10vy=50m/s2
Please approve the answer if helped.

Provide a better Answer & Earn Cool Goodies

star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Other Related Questions on aipmt

question mark
NEET COACHING FOR GRADE 9 STUDENT IN ABU DHABI,UAE. What are the options available
aipmt
0 Answer Available

Last Activity: 3 Years ago

question mark
Explaination on the strength of bonds in the figure
aipmt
0 Answer Available

Last Activity: 3 Years ago

question mark
Mam today in neet ug 2021 due to my nervousness I bubbled one wrong figure of my roll number but I have filled the roll number correctly in the blocks the invigilator adviced me to leave it as it is and to bubble the same correct figure so I did that .am very much worried what will happen
aipmt
0 Answer Available

Last Activity: 3 Years ago

question mark
Magnetic Length of bar magnet of length 70 cm is 63 cm. Want a solution for this.
aipmt
0 Answer Available

Last Activity: 3 Years ago

question mark
in the stomatal apparatus why are subsidiary celss absent in cucurbits?
aipmt
1 Answer Available

Last Activity: 4 Years ago