Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

1ska 1st solve kqr dijiye.iska fisrt solve kar dijiye

1ska 1st solve kqr dijiye.iska fisrt solve kar dijiye

Question Image
Grade:

1 Answers

Arun
25763 Points
one year ago

Number of P species present at time t=0 is 4No

Half life of P is 1 minute

 

After 1st half life the number of P species = 2No

 

After 2nd half life the number of P species = No

After 3rd half life the number of P species = No/2

After 4th half life the number of P species = No/4

Total time = 4 minutes.

Hence, R = 4No– No/4

Number of Q species present at time t=0 is No

Half life of Q is 2 minutes

After 1st half life the number of Q species = No/2

After 2nd half life the number of Q species = No/4

Total time = 4 minutes

Hence, R = No – No/4

Total R = [4No – No/4] + No – No/4 = 15No/4 +3/4 No = 18No/4 = 9No/2

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free