1ska 1st solve kqr dijiye.iska fisrt solve kar dijiye

Number of P species present at time t=0 is 4N_o

Half life of P is 1 minute

After 1^st half life the number of P species = 2N_o

After 2^nd half life the number of P species = N_o

After 3^rd half life the number of P species = N_o/2

After 4^th half life the number of P species = N_o/4

Total time = 4 minutes.

Hence, R = 4N_o– N_o/4

Number of Q species present at time t=0 is N_o

Half life of Q is 2 minutes

After 1^st half life the number of Q species = N_o/2

After 2^nd half life the number of Q species = N_o/4

Total time = 4 minutes

Hence, R = N_o – N_o/4

Total R = [4N_o – N_o/4] + N_o – N_o/4 = 15N_o/4 +3/4 N_o = 18N_o/4 = 9N_o/2