0

Guest

Courses New
  • Forum
  • AIPMT
  • A former has to go 6m due north 8m due east...

A former has to go 6m due north 8m due east and 10m upwards to resch his feild what is distance ? and displecement?

A former has to go 6m due north 8m due east and 10m upwards to resch his feild
what is distance  ?
and displecement?

Grade:12th pass

2 Answers

Manish Sah
15 Points
2 years ago
These three displacements are mutually perpendicular to each other so                                Net disp.(s)=(8^2+6^2+10^2)^1/2=10(2)^1/2m
 
Distance=6+8+10=24m
Vikas TU
14149 Points
2 years ago
First, he goes 6m north, then 8m east and finally 10m north again. So we draw an imaginary triangle to find the displacement. Displacement is the shortest distance between the final point and the initial point. So the shortest distance= √(16^2 + 8^2) = √320= 17.88m or 18m ( approximately)

Think You Can Provide A Better Answer ?

Other Related Questions on AIPMT

View all Questions »

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More