Show that the points A (1, 2), B ( – 1, – 16) and C (0, – 7) lie on the graph of the linear equation y = 9x – 7.

Dear Student



y = 9x – 7

For A (1, 2),

Substituting (x,y) = (1, 2),



2 = 9(1) – 7

2 = 9 – 7

2 = 2

For B (–1, –16),

Substituting (x,y) = (–1, –16),



–16 = 9(–1) – 7

-16 = – 9 – 7

-16 = – 16

For C (0, –7),

Substituting (x,y) = (0, –7),



– 7 = 9(0) – 7

-7 = 0 – 7

-7 = – 7

Hence, the points A (1, 2), B (–1, –16) and C (0, –7) satisfy the line y = 9x – 7.

Thus, A (1, 2), B (–1, –16) and C (0, –7) are solutions of the linear equation y = 9x – 7

Thus, the points A (1, 2), B (–1, –16), C (0, –7) lie on the graph of linear equation y = 9x – 7.


Thanks