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Construct a quadrilateral ABCD in which AB = 4.4 cm, BC = 4 cm, CD = 6.4 cm, DA = 3.8 cm and BD = 6.6 cm.
First, we draw a rough sketch of the quadrilateral ABCD and write down its dimensions along the sides.
We may divide the quadrilateral into two constructible triangles ABD and BCD.
Steps of Construction:
Step I: Draw BD = 6.6 cm
Step II: With B as the center and radius BC = 4 cm, draw an arc.
Step III: With D as the center and radius 6.4 cm, draw an arc to intersect the arc drawn in Step II at C.
Step IV: With B as the center and radius 4.4 cm, draw an arc on the side BD opposite to that of C.
Step V: With D as the center and radius 3.8 cm, draw an arc to intersect the arc drawn in Step IV at A.
Step VI: Join BA, DA, BC and CD The quadrilateral ABCD so obtained is the required quadrilateral.
Construct a quadrilateral ABCD such that AB = BC = 5.5 cm, CD = 4 cm, DA = 6.3 cm and AC = 9.4 cm. Measure BD.
Step I: Draw AB = 5.5 cm
Step II: With B as the center and radius BC = 5.5 cm, draw an arc.
Step III: With A as the center and radius AC = 9.4 cm, draw an arc to intersect the arc drawn in Step II at C.
Step IV: With C as the center and radius CD = 4 cm, draw an arc.
Step V: With A as the center and radius AD = 6.3 cm, draw an arc to intersect the arc drawn in Step IV at D.
Step VI: Join DA, BC, AC, and CD.
The quadrilateral ABCD so obtained is the required quadrilateral.
Construct a quadrilateral XYZW in which XY = 5 cm, YZ = 6 cm, ZW = 7 cm, WX = 3 cm and XZ = 9 cm.
Step I: Draw XZ = 9 cm
Step II: With X as the center and radius 5 cm, draw an arc above XZ.
Step III: With Z as the center and radius 6 cm, draw an arc to intersect the arc drawn in Step II at Y above XZ.
Step IV: With Z as the center and radius 7 cm, draw an arc below XZ.
Step V: With X as the center and radius 3 cm, draw an arc to intersect the arc drawn in Step IV at W below XZ.
Step VI: Join XY, YZ, ZW, and XW.
The quadrilateral WXYZ so obtained is the required quadrilateral.
Construct a parallelogram PQRS such that PQ = 5.2 cm, PR = 6.8 cm and QS = 8.2 cm.
In a parallelogram opposite sides are equal.
Thus, we have to construct a quadrilateral PQRS in which PQ = 5.2 cm, PR = 6.8 cm and QS = 8.2 cm.
Step I: Draw QS = 8.2 cm
Step II: With Q as the center and radius 5.2 cm, draw an arc.
Step III: With S as the center and radius 5.2 cm, draw an arc to intersect the arc drawn in Step II at C.
Step IV: With P as the center and radius 6.8 cm.
Step V: With Q as the center and radius 5.2 cm, draw an arc to intersect the arc drawn in Step IV at A.
Step VI: Join QR, QP, PS, and SR.
The quadrilateral PQRS so obtained is the required quadrilateral.
Construct a rhombus with side 6 cm and one diagonal 8 cm. Measure the other diagonal.
Step 1: Draw AC = 8 cm.
Step 2: With A as the centre and radius = 6 cm, draw arcs on both sides.
Step 3: With C as the center and radius = 6 cm, draw arcs on both sides, intersecting the previous arcs at points B and D.
Step 4: Join BD = 8.9cm.
Thus, ABCD is the required rhombus.
Construct a kite ABCD in which AB = 4 cm, BC = 4.9 cm and AC = 7.2 cm.
Step I: Draw AC = 7.2 cm.
Step II: With A as the centre and radius 4cm, draw arcs on both sides of the line segment AC.
Step III: With C as the centre and radius 4.9 cm, draw arcs on both sides of AC intersecting the previous arcs of step II at B and D.
Step IV: Join BA, DA, BC and CD.
Thus, the quadrilateral ABCD so obtained is the required kite.
Construct, if possible, a quadrilateral ABCD given AB = 6 cm, BC = 3.7 cm, CD = 5.7 cm, AD = 5.5 cm and BD = 6.1 cm. Give reasons for not being able to construct it, if you cannot.
Step I: Draw AB = 6 cm.
Step II: With A as the center and radius 5.5 cm, draw an arc.
Step III: With B as the center and radius 6.1 cm, draw an arc to intersect the arc drawn in Step II at D.
Step IV: With B as the centre and radius 3.7 cm, draw an arc on the side.
Step V: With D as the centre and radius 5.7 cm, draw an arc to intersect the arc drawn in Step IV at C.
Step VI: Join BD, DA, BC and CD.
Construct, if possible, a quadrilateral ABCD in which AB = 6 cm, BC = 7 cm, CD = 3 cm, AD = 5.5 cm and AC = 11 cm. Give reasons for not being able to construct, if you cannot. (Not possible, because in triangle ACD, AD + CD <AC).
Such a quadrilateral cannot be constructed because, in a triangle, the sum of the length of its two sides must be greater than that of the third side
But here in triangle ACD,
AD + CD = 5.5 + 3 = 8.5 cm
and AC = 11 cm
i.e., AD + CD < AC, which is not possible.
So, the construction is not possible.
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