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The polar form of a complex number z = x + iy, is given by z = |z| (cos θ + i sin θ)
where,
Let z = 1 + i
∵ x, y > 0, so θ lies in first quadrant
Now,
The polar form of a complex number z = x + iy, is givenby z = |z| (cos θ + i sin θ)
Where,
= 2
∵ x = √3. 0 & y = 1 > 0,
∴ θ lies in first quadrant
Hence
= tan-1 (∵ tan-1) (tan x) = x)
polar form is given by z = |z|(cos θ + i sin θ)
Polar Form, z = r (cos θ + i sin θ)
The polar form of a complex number z = x + iy, is given by z = |z| (cos θ + i sin θ)
Here z is already inpolar form
= 8
Here x = – 4 < 0 & y = 4R3 > 0, ∴ θ lies in quadrant II
z = (i25)3 = (i)3 = – i
|z| = 1,
Let z = 1 + i tan α
tan α is periodic fun function with period π.
tan β = |tan α| = tan α
⟹ β = α
As z is represented by a point in first quadrant.
∴ arg(z) = β = α
So polar form of z is secα (cos α + i sin α)
tan β = |tan α| = – tan α = tan(π – α)
⟹ β = π – α
As z is represented by a point in fourth quadrant.
∴ arg(z) = – β = α – π.
So polar form of z is-secα (cos (α – π) + i sin (α – π)).
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Chapter 13: Complex Numbers – Exercise 13.2...
Chapter 13: Complex Numbers – Exercise 13.3...
Chapter 13: Complex Numbers – Exercise 13.1...