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Let z = – 5 + 12i
Let z = – 7 – 24i
Let z = 1 – i
Let z = – 8 – 6i
Let z = 8 – 15i
Let z = 4i
then |z| = |4i|
= 4|i| (∵ |z1 z2 | = |z1 |×|z2|)
= 4 (∵ | i | = 1)
Let z = – i
then |z| = | – i |
= | – 1| × |i| (∵ |z1 z2 | = |z1| × |z2|)
= 1 × i (∵ | i | = 1)
Chapter 13: Complex Numbers – Exercise 13.4...
Chapter 13: Complex Numbers – Exercise 13.2...
Chapter 13: Complex Numbers – Exercise 13.1...