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the light of wavelength 6328 angstrom is incident on a slit of width 0.2 mm perpendicularly, what will be the angular fringe width of central maxima ?

the light of wavelength 6328 angstrom is incident on a slit of width 0.2 mm perpendicularly, what will be the angular fringe width of central maxima ?

Grade:12th pass

2 Answers

Vikas TU
14149 Points
5 years ago
    Here , given
 Wavelength  = 6328 angstrom
Width = 0.2 mm
Then the angular fringe width will be = wavelength / width
                                = 6.3 * 10^-5 /0.2 * 10^-3
                                = 31.5o
Kashif Ali
13 Points
2 years ago
Here given Wavelength=6328angstrom Width=0.2mm Angular fringe width=Wavelength/Width 6328

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