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Grade 12th passWave Optics

the light of wavelength 6328 angstrom is incident on a slit of width 0.2 mm perpendicularly, what will be the angular fringe width of central maxima ?

Profile image of Arijit Mandal
9 Years agoGrade 12th pass
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2 Answers

Profile image of Vikas TU
9 Years ago
    Here , given
 Wavelength  = 6328 angstrom
Width = 0.2 mm
Then the angular fringe width will be = wavelength / width
                                = 6.3 * 10^-5 /0.2 * 10^-3
                                = 31.5o
Profile image of Kashif Ali
5 Years ago
Here given Wavelength=6328angstrom Width=0.2mm Angular fringe width=Wavelength/Width 6328

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