in interference of light , the ratio of maximum to minimum intensities in the fring system is 9 : 1 . find the ratio of amplitudes of the sources.

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Arun · Answer

Dear student As we know I a^2 hence 9 : 1 = [a1 / a2]^2 Hence a1 / a2 = 3 : 1 Regards Arun (askIITians forum expert)

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in interference of light , the ratio of maximum to minimum intensities in the fring system is 9 : 1 . find the ratio of amplitudes of the sources.

in interference of light , the ratio of maximum to minimum intensities in the fring system is 9 : 1 . find the ratio of amplitudes of the sources.

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in interference of light , the ratio of maximum to minimum intensities in the fring system is 9 : 1 . find the ratio of amplitudes of the sources.

in interference of light , the ratio of maximum to minimum intensities in the fring system is 9 : 1 . find the ratio of amplitudes of the sources.

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