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in interference of light , the ratio of maximum to minimum intensities in the fring system is 9 : 1 . find the ratio of amplitudes of the sources.

Kadam vikrant , 7 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 7 Years ago

Dear student
 
As we know
I  \alpha  a^2
hence
9 : 1 = [a1 / a2]^2
Hence
a1 / a2 = 3 : 1
 
Regards
Arun (askIITians forum expert)

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