in interference of light , the ratio of maximum to minimum intensities in the fring system is 9 : 1 . find the ratio of amplitudes of the sources.

Arun
25758 Points
4 years ago
Dear student

As we know
I  $\alpha$  a^2
hence
9 : 1 = [a1 / a2]^2
Hence
a1 / a2 = 3 : 1

Regards