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# in interference of light , the ratio of maximum to minimum intensities in the fring system is 9 : 1 . find the ratio of amplitudes of the sources.

Arun
25763 Points
3 years ago
Dear student

As we know
I  $\alpha$  a^2
hence
9 : 1 = [a1 / a2]^2
Hence
a1 / a2 = 3 : 1

Regards