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consider a tank made of glass (refractive index 1.5) with a thick bottom. It is filled with a liquid of refractive index μ. A student finds that irrespective of what the incident angle is for a beam of light entering the liquid, the light reflected from the glass interface is never completely polarised. For this to happen, the minimum value of μ is √5 /√3 3/√5 5/√3 4/3 plz explain also

 
consider a tank made of glass (refractive index 1.5) with a thick bottom. It is filled with a liquid of refractive index μ. A student finds that irrespective of what the incident angle is for a beam of light entering the liquid, the light reflected from the glass interface is never completely polarised. For this to happen, the minimum value of μ is
 
  1. √5 /√3
  2. 3/√5
  3. 5/√3
  4. 4/3
plz explain also

Grade:12th pass

2 Answers

Vikas TU
14149 Points
3 years ago
Dear student 
C
Sin C
1/mu
sin ib = ( 1 )
root ( mu ^ 2 + 1.5 ^ 2 )
mu ^ 2 + 1.5 ^2
mu 3/ root 5
Vikas TU
14149 Points
3 years ago
C is less than ib and c is criticle angle 
Sin c less than Sin ib a
Tan ib = mu ref = 1.5/mu
1/mu is less than 1.5 /root mu^2 + root(1.5)^2 
sin ib = 1 
root (mu^2) +1.5^2) is less than mu*1.5 
mu^2 + 1.5^2 is less than (mu*1.5)^2 
mu less than 3/ root5 

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