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At two points P and Q on a screen in Young`s double slit experiment, waves from slit S1 and S2 have a path difference of 0 and lambda/4 respectively. Then ratio of intensities at P and Q will be ?
path difference 0,lambda/4so phase difference 0, pi/2in case of zero, intensity= (2*sqrt(I))^2=4Iin cese of pi/2 I+I+2*sqrt(I*I)cos(pi/2)=2Iso I at P/I at Q=2thanks and regardsSher MOhammadfaculty askiitians
Dear student,Pleae find the solution to your problem. path difference = 0, λ/4so phase difference = 0, π/2 in case of 0 phase difference, intensity = (2√I)2 = 4Iin cese of π/2 phase difference, I + I + 2√(I*I)cos(π/2) = 2Iso (I at P):(I at Q) = 2:1 Thanks and regards,Kushagra
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