At two points P and Q on a screen in Young`s double slit experiment, waves from slit S1 and S2 have a path difference of 0 and lambda/4 respectively. Then ratio of intensities at P and Q will be ?

Question

Sher Mohammad · Answer

path difference 0,lambda/4

so phase difference 0, pi/2

in case of zero, intensity= (2*sqrt(I))^2=4I

in cese of pi/2 I+I+2*sqrt(I*I)cos(pi/2)=2I

so I at P/I at Q=2

thanks and regards

Sher MOhammad

faculty askiitians

Kushagra Madhukar · Answer

Dear student, Pleae find the solution to your problem. path difference = 0, λ/4 so phase difference = 0, π /2 in case of 0 phase difference, intensity = (2 √ I) 2 = 4I in cese of π /2 phase difference, I + I + 2 √ (I*I)cos( π /2) = 2I so (I at P):(I at Q) = 2:1 Thanks and regards, Kushagra

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At two points P and Q on a screen in Young`s double slit experiment, waves from slit S1 and S2 have a path difference of 0 and lambda/4 respectively. Then ratio of intensities at P and Q will be ?

At two points P and Q on a screen in Young`s double slit experiment, waves from slit S1 and S2 have a path difference of 0 and lambda/4 respectively. Then ratio of intensities at P and Q will be ?

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