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At two points P and Q on a screen in Young`s double slit experiment, waves from slit S1 and S2 have a path difference of 0 and lambda/4 respectively. Then ratio of intensities at P and Q will be ?

Akash , 11 Years ago
Grade 12th pass
anser 2 Answers
Sher Mohammad

Last Activity: 11 Years ago

path difference 0,lambda/4

so phase difference 0, pi/2

in case of zero, intensity= (2*sqrt(I))^2=4I
in cese of pi/2 I+I+2*sqrt(I*I)cos(pi/2)=2I

so I at P/I at Q=2


thanks and regards
Sher MOhammad
faculty askiitians

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,
Pleae find the solution to your problem.
 
path difference = 0, λ/4
so phase difference = 0, π/2
 
in case of 0 phase difference, intensity = (2√I)2 = 4I
in cese of π/2 phase difference, I + I + 2√(I*I)cos(π/2) = 2I
so (I at P):(I at Q) = 2:1
 
Thanks and regards,
Kushagra

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