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Grade: 12th pass
        
A point object at 15 cm from concave mirror of radius of curvature 20cm is made to oscillate along principle axis with amplitude of 2mm. Find amplitude of its image. .
14 days ago

Answers : (1)

Arun
16262 Points
							
Transverse magnification = mT = -v/u
 
1/v + 1/u = 1/f
 
v = – 30 cm
 
now mt = – v/u = – 2
 
mL = – mt^2 = – 4
 
- dv/du = -4
 
dv = 8mm
 
hence ampkitude of image oscillation is 8 mm
14 days ago
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