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Two particles execute SHM of same amplitude of 20 cm with same period along the same line about the same equilibrium position.If the phase differnce between them is pi/3 find the maximum distance between them

Two particles execute SHM of same amplitude of 20 cm with same period along the
same line about the same equilibrium position.If the phase differnce between them is pi/3 find the maximum distance between them

Grade:12th pass

1 Answers

Shaikh Muzzakir
45 Points
3 years ago
Find:Maximum distances (R)Data:A1=A2=A=20 cm.Phase difference (d)= π÷3=60°.Formula:R=√A1^2+A2^2+A1A2cosd. ....^ means power.Solution:From formula,.R=√20^2+20^2+2×20×20×cos60°.R=√400+400+800÷0.5.R=√400+400+400.R=√3(400).R=20√3.R=20(1.73).R=34.6 cm.

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