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Grade: 12th pass

                        

Two particles execute SHM of same amplitude of 20 cm with same period along the same line about the same equilibrium position.If the phase differnce between them is pi/3 find the maximum distance between them

3 years ago

Answers : (1)

Shaikh Muzzakir
45 Points
							Find:Maximum distances (R)Data:A1=A2=A=20 cm.Phase difference (d)= π÷3=60°.Formula:R=√A1^2+A2^2+A1A2cosd.    ....^ means power.Solution:From formula,.R=√20^2+20^2+2×20×20×cos60°.R=√400+400+800÷0.5.R=√400+400+400.R=√3(400).R=20√3.R=20(1.73).R=34.6 cm.
						
2 years ago
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