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The potential energy of a particle executing shm with amplitude a is e at extreme position what is its k.e at y=a/2?

Medical Student , 7 Years ago
Grade 12th pass
anser 1 Answers
Khimraj

Last Activity: 7 Years ago

Total energy of of particle executing shm T.E.= max kinetic energy = ½ mω2a2
At extreme position kinwtic energy will be  zero So Potential energy at extreme position P.E. = T.E. = ½ mω2a2 = e(given)
then Kinetic energy at y = a/2
K = ½ mω2[a2 – a2/4]
So, K.E. = ¾ (½ mω2a2)
K.E. = ¾ e
Hope it clears. If you like answer then please approve it.
 

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