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Grade: 12

                        

pls help......................................................................

6 months ago

Answers : (3)

Parth
58 Points
							
in this question you’ve to use the concept of the circle of illuminance
A = Angle at which total internal reflection is occurring, in this case, it is given by sin(A) = 1/mu. mu = 4/3;
A = 48.5903 degrees ; 
in this case percentage of light escaped = [1 – cos(A)]/2 which gives 0.169281 which is nearly 16.92% or 17 %
5 months ago
Parth
58 Points
							
in this question you’ve to use the concept of the circle of illuminance
A = Angle at which total internal reflection is occurring, in this case, it is given by sin(A) = 1/mu. mu = 4/3;
A = 48.5903 degrees ; 
in this case percentage of light escaped = [1 – cos(A)]/2 which gives 0.169281 which is nearly 16.92% or 17 %
pls approve
5 months ago
Arun
24734 Points
							
Dear student
 
A = Angle at which total internal reflection is occurring, in this case, it is given by sin(A) = 1/mu. mu = 4/3;
A = 48.5903 degrees ; 
in this case percentage of light escaped = [1 – cos(A)]/2 which gives 0.169281 which is nearly 16.92% 
 
Hope it helps
 
5 months ago
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