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Arun
25763 Points
one year ago
First find the Velocity in the direction of Observer from Source
Which is vcos∅ = 20m/s × 1/2 {cos∅=Base/Hypotenuse}
... v = 10m/s
Now apply formula of Doppler's effect
μ'=μ×v/(v-v°)
μ'=640×330/330-10
μ'=640×330/320
μ'=660 Hz
Where μ'→Final Frequency and μ→Initial frequency

Vikas TU
14149 Points
one year ago
In the above figure s is the position of locomotive and O is the position of observer when the locomotive whistle.
Angle SAO = 90
AO = 0.6 mile
SA = 1 mile
Component of Vs along SO
V' = Vs CosQ
CosQ = SA/SO
= 0.857
Speed of locomotive = 80 mile/hour = 0.22mile/sec
Therefor
V' = 0.22 * 0.857 = 0.019 mile/sec
The apparent frequency when source is in motion
f = 0.20/(0.20-0.019) *400 = 442 Hz