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calculate the frequency of the fundamental note produced by a string 1 m long and weighing 2 g kept stretched by a load 400 kg
direct substitution answer.. :) f=?, l=1m, T(tension)=400N, m(=mass/length)=2*10-3...substitute..u get the answer.. :)
the fundamental frequency is=[(200000)^1/2]/2=223.6 hzI think iam correct.if u have any further doubts please post them.thank u.
Tension is mass multiplied by acceleration due to to gravity. So using formula f=1/2L (T/m) ^1/2. Where m is mass per unit lengththe answer will be around 700Hz
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