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A spring of constant K is cut into two parts by ratio 1:2. The spring constant K of larger one is?
answer is 3K/2 but how?

shy , 7 Years ago
Grade 12th pass
anser 1 Answers
Khimraj
K / K’ = (2L / 3) / L
K / K’ = 2 / 3
K’ = 3K / 2
K’ = 1.5 K

Force constant of larger piece is 1.5 K
Hope it clears..........................
Last Activity: 7 Years ago
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