Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
A car travelling 60km. /h Overtakes another car travelling at 42km./h. Asuming each car to be 5mtr. long . Find time taken during the Overtake. and road distance.
For the car with 60kmph to overtake the first car it should travel a relative distance of 10 m
(5m for catching up and 5m for getting clear ahead)
therefore Srel = 10 m
Vrel = 60-42 = 18km/hr = 5 m/s
Relative acceleration = 0 .since both are moving with constant velocities.
Now using relative motion, S = Vrel × t
therefore time ,t = S / Vrel = 10/5 = 2s
Distance used to overtake is 60 × 5/18 × 2 = 100/3 = 33.33 m
As the second car overtakes the first one the total distance travelled by the second car will be 5m + 5m = 10m.
Now, let the time taken to overtake the car be t seconds
Therefore,
distance travelled by seconds car in time t = distance travelled by first car in t + total overtaking distance, so
60t=42t+0.01
or
t=1/1800hr or 2s
Therefore time required to overtake the car is 2 seconds.
Distance travelled in that time will be
2s= 5 + 60*1/1800*1000
=5+60/1.8 =5+33.33
=38.33 m
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !