If four points whose position vectors are a, b, c and d are coplanar, show that (a*b*c) = (a*d*b) + (a*d*c) + (d*b*c)

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Gundeti Sailu · Answer

-3 IT is because that all are coplanar {abc]=[bcd]=[cda]=[dab] so by interchanging positions we get all=[-abc]

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If four points whose position vectors are a, b, c and d are coplanar, show that (abc) = (adb) + (adc) + (dbc)

If four points whose position vectors are a, b, c and d are coplanar, show that (abc) = (adb) + (adc) + (dbc)

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If four points whose position vectors are a, b, c and d are coplanar, show that (a*b*c) = (a*d*b) + (a*d*c) + (d*b*c)

If four points whose position vectors are a, b, c and d are coplanar, show that (a*b*c) = (a*d*b) + (a*d*c) + (d*b*c)

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If four points whose position vectors are a, b, c and d are coplanar, show that (abc) = (adb) + (adc) + (dbc)

If four points whose position vectors are a, b, c and d are coplanar, show that (abc) = (adb) + (adc) + (dbc)