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For what value of a will the vectors 3i-2j+k and 2i-j+ab be perpendicular

vartika , 8 Years ago
Grade 12th pass
anser 1 Answers
Arun
for them to be perpendicular, their dot product should be zero
hence,
(3i –2j+k).(2i –j+ak) = 0
6+2+a = 0
a= –8
hope it helps
Last Activity: 8 Years ago
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