The question is from 3 D geometry and it is seen in the attachment .

Question

Aditya Gupta · Answer

assume eqn of plane to be ax+by+cz+d=0 it passes through (2,1,2) and (1,2,1) so put x,y,z as these pts to obtain 2 eqns in a b c d. normal vector of this plane is n = ai+bj+ck. write line 2x=3y and z=1 in std form as x/3= y/2= (z – 1)/0, with DR’s 3,2,0 for parallel, apply the conditon n. (3i+2j+0k)=0 3a+2b=0 solving these eqns u ll get b c and d in terms of a. now write ax+by+cz+d=0 as x+py+qz+r=0 where p=b/a, q=c/a, r=d/a (which can be calculated using above eqns) KINDLY APPROVE :))

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The question is from 3 D geometry and it is seen in the attachment .

The question is from 3 D geometry and it is seen in the attachment .

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