 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
For two equal non parallel forces acting a a point the square of resultant is 3 times the product of forces, what is angle between forces

```
3 years ago

```							Given two forces P and Q, such that | P | = P, | Q | = Q, and P = Q, acting at a point, such that square of magnitude R of resultant R of P and Q is 3 P² = 3 Q². We are required to find the angle between P and Q.Let the angle between P and Q is ∅. Then by parallelogram law of vectors we have for the resultant, that,R² = P² + Q² + 2 P Q Cos ∅ = P² + P² + 2 P P Cos ∅= 2 P² + 2 P² Cos ∅. ……..(1)We are given that R² = 3 P². Substituting for R² in equation 1, we get,3 P² = 2 P² + 2 P² Cos ∅, or Cos ∅ = ½ or ∅ = 60° .The angle between the two forces is 60°
```
3 years ago
```							Assume the Force be A, B and resultant be CGiven C2=A2+B2+2ABCOS(THETA)GIVEN A=BSO C2=2A2+2A2COS(THETA)NOW C2=3A2SO 3A2=2A2+2A2COS(tHETA)S Cos(theta)=1/2SO ANGLE WILL BE 60 DEGREE
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Vectors

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 19 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions