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a rigid body OA vecter = 3i+6j+2k.find velocity of the point P of the body whose position vector is i,j,k?
ω= 3 radian/secOA = 3i + 6j + 2kSo we can asume that OA vector's starting point is O and end point is A. So when vector OA rotate with respect to the point O , it makes a circle, whose position vector r = OA= 3i+6j+2k.So we have ω, and r. As we know that velocity v =r * ωSo v= 3* (3i+6j+2k)So velocity V= 9i + 18j + 6k
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