0

Guest

Courses New

a rigid body OA vecter = 3i+6j+2k.find velocity of the point P of the body whose position vector is i,j,k?

a rigid body OA vecter = 3i+6j+2k.find velocity of the point P of the body whose position vector is i,j,k?

Question Image
Grade:12th pass

1 Answers

Aashrut
27 Points
3 years ago
ω= 3 radian/sec
OA = 3i + 6j + 2k
So we can asume that OA vector's starting point is O and end point is A. So when vector OA rotate with respect to the point O , it makes a circle, whose position vector r = OA= 3i+6j+2k.
So we have ω, and r. 
As we know that velocity v =r * ω
So v= 3* (3i+6j+2k)
So velocity V= 9i + 18j + 6k

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Vectors

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More