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a rigid body OA vecter = 3i+6j+2k.find velocity of the point P of the body whose position vector is i,j,k?

Amin Uddin , 6 Years ago
Grade 12th pass
anser 1 Answers
Aashrut
ω= 3 radian/sec
OA = 3i + 6j + 2k
So we can asume that OA vector's starting point is O and end point is A. So when vector OA rotate with respect to the point O , it makes a circle, whose position vector r = OA= 3i+6j+2k.
So we have ω, and r. 
As we know that velocity v =r * ω
So v= 3* (3i+6j+2k)
So velocity V= 9i + 18j + 6k
Last Activity: 6 Years ago
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