A force of 60n is acting perpendicular to the force of 80n magnitude of resultant force is (a) 20n (b) 70n (C) 100n (D) 140n

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Nitin · Answer

[c] 100 Newton using Pythagoras theorem i.e sqrt[60 2 +80 2 ] Method two: Let the force be : 80i+60j Now take the magnitude. of the vector

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A force of 60n is acting perpendicular to the force of 80n magnitude of resultant force is (a) 20n (b) 70n (C) 100n (D) 140n

A force of 60n is acting perpendicular to the force of 80n magnitude of resultant force is (a) 20n (b) 70n (C) 100n (D) 140n

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A force of 60n is acting perpendicular to the force of 80n magnitude of resultant force is (a) 20n (b) 70n (C) 100n (D) 140n

A force of 60n is acting perpendicular to the force of 80n magnitude of resultant force is (a) 20n (b) 70n (C) 100n (D) 140n

1 Answers

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