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The locus of a point equidistant from two given points a and b is given by
Dear pallavi
locus of point will be perpendicular bisector of these two vector.
let the general point on the line is r
so line will pass through (a+b)/2
and r-(a+b)/2 and (b-a) will be perpendicular
so {r-(a+b)/2 }.(b-a) =0
r.(b-a) =1/2( |b|2 -|a|2)
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All the best. Regards,Askiitians ExpertsBadiuddin
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