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WHAT IS THE SQUARE ROOT OF -i? WRITE THE ARGUMENT OF -i.

WHAT IS THE SQUARE ROOT OF -i?


 


WRITE THE ARGUMENT OF -i.

Grade:11

3 Answers

Akash Kumar Dutta
98 Points
8 years ago

find sq root by the simple step... root (-i)=a+ib...............
and arg of -i= -pi/2 or 5pi/2

Rohan Nambiar
17 Points
8 years ago

sqr root of -i is +or-(1-i)/21/2 and argument is -∏/2

Abhishekh kumar sharma
34 Points
8 years ago

let (a+ib)^2=-i then calculate and b to get the z=√-i

which is +-1 which turn to get arg(z)=pie\4

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