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Let P be the point that divides the line segment AB in the ration AP:PB=m:n.
If O is the origin show that
OP=(n/m+n)OA + (m/m+n)OB
Dear student,
Let O be the origin. The , let be the position vector of C which divides AB internally in the ratio m : n then,
AC/CB = m/n
=> n.
=> n(P.V. of – P.V. of ) = m(P.V. of – P.V. of )
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