If sec (a+b) + sec(a-b)=2seca and cosb not equal to 1 , then show that cos0=+or-root under 2 multiplied by cosa/2

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Saurabh Koranglekar · Answer

Dear student Please attach the question's image or source so that it is clear what is to be proved Is it cos (a/2) or ( cos a )/2 Regards

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If sec (a+b) + sec(a-b)=2seca and cosb not equal to 1 , then show that cos0=+or-root under 2 multiplied by cosa/2

If sec (a+b) + sec(a-b)=2seca and cosb not equal to 1 , then show that cos0=+or-root under 2 multiplied by cosa/2

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If sec (a+b) + sec(a-b)=2seca and cosb not equal to 1 , then show that cos0=+or-root under 2 multiplied by cosa/2

If sec (a+b) + sec(a-b)=2seca and cosb not equal to 1 , then show that cos0=+or-root under 2 multiplied by cosa/2

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