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The maximum and minimum value of the question cos²(45-x)+(sinx-cosx)²

The maximum and minimum value of the question cos²(45-x)+(sinx-cosx)²

Grade:8

1 Answers

Aditya Gupta
2081 Points
5 years ago
On expanding the entire term, we get
(1+2sc)/2+ 1-2sc, where s and c are sinx and cosx.
This is equal to 3/2-sc. But sc= sin2x/2. So it becomes
(3-siny)/2, y=2x
As sinx lies in -1 to 1 so the above expression lies in 1 to 2. Hence minimum and maximum values are 1 and 2 respectively

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