sum of integral values of n such that sin x(2sinx+cosx)=n, has at least one real solution is (a)0 (b)1 (c)2 (d)3

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Arun · Answer

2 sin^2x + 2sinx cosx/2 = n sin2x+ 2(1-cos2x) = 2n Sin2x - 2 cos2x = 2(n-1) - 5 5 1 - 5/2 5/2 Hence integral values of n = 0 , 1 , 2 total number of integral value = 3 (option D)

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sum of integral values of n such that sin x(2sinx+cosx)=n, has at least one real solution is (a)0 (b)1 (c)2 (d)3

sum of integral values of n such that sin x(2sinx+cosx)=n, has at least one real solution is
(a)0 (b)1 (c)2 (d)3

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sum of integral values of n such that sin x(2sinx+cosx)=n, has at least one real solution is (a)0 (b)1 (c)2 (d)3

sum of integral values of n such that sin x(2sinx+cosx)=n, has at least one real solution is(a)0 (b)1 (c)2 (d)3

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sum of integral values of n such that sin x(2sinx+cosx)=n, has at least one real solution is
(a)0 (b)1 (c)2 (d)3