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Grade: 12th pass
        
Please solve the problem in the attachment....... .......... 
4 months ago

Answers : (2)

Rajat
137 Points
							
Cauchy Schawtz Inequality states that,
(\sum aibi)^2\leq (\sum ai^2)(\sum bi^2)
Thus by plugging a,b,c in place of ai's and sinx,siny,sinz in place of bi's we get,(asinx+bsiny+csinz)^2\leq (sin^2x+sin^2y+sin^2z)(a^2+b^2+c^2) or,(sin^2x+sin^2y+sin^2z)\geq k^2/(a^2+b^2+c^2) so min value required = k^2/(a^2+b^2+c^2)
 
Sorry I am using alpha=x, beta=y and gamma=z
 
 
So min value reqd = k
4 months ago
Rajat
137 Points
							
Pardon me Don't mind the last line, typing error occured....
The actual minimum value reqd is k^2/(a^2+b^2+c^2)
4 months ago
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