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        Please solve the problem in the attachment....... ..........
7 months ago

Rajat
213 Points
							Cauchy Schawtz Inequality states that,$(\sum aibi)^2\leq (\sum ai^2)(\sum bi^2)$Thus by plugging a,b,c in place of ai's and sinx,siny,sinz in place of bi's we get,$(asinx+bsiny+csinz)^2\leq (sin^2x+sin^2y+sin^2z)(a^2+b^2+c^2) or,(sin^2x+sin^2y+sin^2z)\geq k^2/(a^2+b^2+c^2)$ so min value required = k^2/(a^2+b^2+c^2) Sorry I am using alpha=x, beta=y and gamma=z  So min value reqd = k

7 months ago
Rajat
213 Points
							Pardon me Don't mind the last line, typing error occured....The actual minimum value reqd is k^2/(a^2+b^2+c^2)

7 months ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions