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Kindly tell last question...value of tan alpha..........plxxx see image


one year ago

Arun
24737 Points
							Dear student I have solved reverse. question Hope it helpsIn case of any difficulty, please feel free to ask again. RegardsArun (askIITians forum expert)

one year ago
2056 Points
							hello tanisha this ques can be easily solved by applying two things: componendo and dividendo, and the formula cos2x= (1 – t^2)/(1+t^2) where t= tanxso the given expression is (1 – t^2)/(1+t^2)= (3cos2b – 1)/(3 – cos2b) where t= tanalphanow apply C n D. – 2t^2/2= 4(cos2b – 1)/2(cos2b+1)or t^2= 2(1 – cos2b)/(cos2b+1)= 2tan^2b (here we have also used (1 – cos2x)/(1+cos2x)= tan^2x)hence t= tanalpha= ± tanb*root2so both options (1) and (2) are correct.kndly approve :)

one year ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions