Grade 11Trigonometry
in a triangle ABC if cos A = 17/22 , cos C =1/14
in a triangle ABC if cos A = 17/22 , cos C =1/14 provve that the ratio of the sides 7:9:11
2 Answers
cos A=17/22
AB/AC=17/22
cos C=1/14
BC/AC=1/14
Now we should equate both the denominator.
AB/AC=17×7/22×7
AB/AC=119/154
BC/AC=1×11/14×11
BC/AC=11/154
THEREFORE,
AB=119 units
BC=11 units
AC=154 units
ratio=119:11:154
My answer is 119:11:154
I think that the question is wrong.
Sin a =√195/22
Sin c =√195/14
Sin B = sin(180-A-C)
Sin(A+C)
SinAcosC+cosAsinC
= 9√195/154
a:b:c= 7:9:11
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