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IN a traingle A,B AND C.then proove TANA +TANB+TANC=?

Gowri sankar , 9 Years ago
Grade 12
anser 12 Answers
SAI SARDAR

Last Activity: 9 Years ago

Gowri Sankar, In triangle abc a+b+c=180 then tan a + tan b + tanc = tanatanbtanc.It is from trigonametric identity.

Prabhakar ch

Last Activity: 9 Years ago

Dear Gowri Shankar
                                It would prove by some trignometric idinaties
This image tells how to proove that formulae
All the best for your bright future

N JYOTHEESWAR

Last Activity: 9 Years ago

dear gowrisankar
                        the total angle in the triangle is 180.in triangle a+b+c=180. then the angles tana+tanb+tanc=180.ie .. tanatanbtanc.this is from trigonometric identities.

T.kumar

Last Activity: 9 Years ago

dear gowri shankar ,
                                  in this triangle a b c total angels is 180 indiviusally one is 60. 2nd is 60. 3rd is 60. all the best.

Gaddam Chethan

Last Activity: 9 Years ago

Hello Gowri
                      we know that a+b+c=180. with these tanA+tanB+thaC=tanAtanBtanC. Aee the best for your bright future.

raj

Last Activity: 9 Years ago

hellow gowrishankar if A,B and C in a triangle then tanA+tanB+tanC=tanA .tanB.tanC this is proves through angles of trigonametri.

NAGOORVALI

Last Activity: 9 Years ago

dear friend in triangle abc tana+tanb+tanc=tanatanbtanc you try this way in triangle a+b+c=180 then b+c=180-a apply tan on both sides

sreekanth sree

Last Activity: 9 Years ago

hello gowri sankar we know that the total angle in the triangle is 180,a+b+c=180,tan a+tan b+tan c=tan a tan b tan c.this is trignometric identities.

sudarshan

Last Activity: 9 Years ago

In triangle abc a+b+c=180 then tan a + tan b + tanc = tanatanbtanc.It is from trigonametric identity.
 

naresh raju

Last Activity: 9 Years ago

DEAR GOWRI,
IN the triangle A,B and C  A+B+C=180 then tanA+tanB+tanC=tanAtanBtanC.it could be solved by some trignometriv identities.

Dheeru chowdary

Last Activity: 9 Years ago

mr.gowri,
    it can be proved by using a+b+c=180.,
           and the answer is tanAtanBtanC which is an trignometry identity
 

Praveen

Last Activity: 8 Years ago

tan(a+b+c)=(tan a+tan b+tan c – tana*tanb*tanc) /(1 - tan a *tan b – tan*b tanc- tan a*tanc)
 since
     a+b+c=180, so tan(a+b+c)=0,
then
tan a+tan b+tan c – tana*tanb*tanc=0
tan a+tan b+tan c = tana*tanb*tanc

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