IN a traingle A,B AND C.then proove TANA +TANB+TANC=?

Gowri Sankar, In triangle abc a+b+c=180 then tan a + tan b + tanc = tanatanbtanc.It is from trigonametric identity.

Dear Gowri Shankar

                                It would prove by some trignometric idinaties

This image tells how to proove that formulae

All the best for your bright future

dear gowrisankar

                        the total angle in the triangle is 180.in triangle a+b+c=180. then the angles tana+tanb+tanc=180.ie .. tanatanbtanc.this is from trigonometric identities.

dear gowri shankar ,

                                  in this triangle a b c total angels is 180 indiviusally one is 60. 2^nd is 60. 3^rd is 60. all the best.

Hello Gowri

                      we know that a+b+c=180. with these tanA+tanB+thaC=tanAtanBtanC. Aee the best for your bright future.

In triangle abc a+b+c=180 then tan a + tan b + tanc = tanatanbtanc.It is from trigonametric identity.

DEAR GOWRI,

IN the triangle A,B and C  A+B+C=180 then tanA+tanB+tanC=tanAtanBtanC.it could be solved by some trignometriv identities.

mr.gowri,

    it can be proved by using a+b+c=180.,

           and the answer is tanAtanBtanC which is an trignometry identity
 

tan(a+b+c)=(tan a+tan b+tan c – tana*tanb*tanc) /(1 - tan a *tan b – tan*b tanc- tan a*tanc)

 since

     a+b+c=180, so tan(a+b+c)=0,

then

tan a+tan b+tan c – tana*tanb*tanc=0

tan a+tan b+tan c = tana*tanb*tanc