If x= a cos^3A, y=a sin^3 A then a) x^2/3 +y^2/3= a^2/3 B) x^2+y^2=a^2 c) y^2 =4ax

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Vikas TU · Answer

Dear Nidhi, x= a cos^3A then cos A = (x/a)^(1/3)......................(1) y=a sin^3 A sin A = (y/a)^(1/3)..................................(2) squaring eqns. (1) and (2) (sin^2A + cos^2A) = (x/a)^(2/3) + (y/a)^(2/3) (x/a)^(2/3) + (y/a)^(2/3) = 1 x^2/3 + y^2/3 = a^2/3 option A plz approve!

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If x= a cos^3A, y=a sin^3 A then a) x^2/3 +y^2/3= a^2/3 B) x^2+y^2=a^2 c) y^2 =4ax

If x= a cos^3A, y=a sin^3 A then
a) x^2/3 +y^2/3= a^2/3
B) x^2+y^2=a^2
c) y^2 =4ax

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If x= a cos^3A, y=a sin^3 A then a) x^2/3 +y^2/3= a^2/3 B) x^2+y^2=a^2 c) y^2 =4ax

If x= a cos^3A, y=a sin^3 A then a) x^2/3 +y^2/3= a^2/3B) x^2+y^2=a^2c) y^2 =4ax

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If x= a cos^3A, y=a sin^3 A then
a) x^2/3 +y^2/3= a^2/3
B) x^2+y^2=a^2
c) y^2 =4ax