Grade 11Trigonometry
IF A+B+C = 3 PIE / 2, THEN COS 2A + COS 2B + COS 2C IS
IF A+B+C = 3 PIE / 2, THEN COS 2A + COS 2B + COS 2C IS
1 Answer
Nishant Vora
Hello student, Please find the answer to your question below
use the following formula for the first 2 terms,
CosC + CosD = 2Cos[(C+D)/2]Cos[(C-D)/2]
then cos 2c is cos (2pi – (2A + 2 B))
Now you can simplify and get the answer….….….….
use the following formula for the first 2 terms,
CosC + CosD = 2Cos[(C+D)/2]Cos[(C-D)/2]
then cos 2c is cos (2pi – (2A + 2 B))
Now you can simplify and get the answer….….….….
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