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Grade: 12

                        

1+tan2A/1+cot2A = (A) sec2 A (B) -1 (C) cot2A (D) tan2A

1+tan2A/1+cot2A =
(A) sec2 A (B) -1 (C) cot2A (D) tan2A

4 months ago

Answers : (2)

Anand Kumar Pandey
askIITians Faculty
4240 Points
							Dear Student

option (D) is correct.

Justification:
We know that,
tan^2 A =1/cot^2 A
Now, substitute this in the given problem, we get

1+tan^2 A/1+cot^2 A
= (1+1/cot^2 A)/1+cot^2 A
= (cot^2 A+1/cot^2 A)×(1/1+cot^2 A) = 1/cot^2 A = tan^2 A
So, 1+tan^2 A/1+cot^2 A = tan^2 A
Thanks
4 months ago
surya prakash
17 Points
							
Welcome to askIITians,
 
we know that 1 + Cot 2A =( 1 + Tan 2A ) / Tan 2A
 
Given that  (1 + Tan 2A )/ ( 1 + Cot 2A)
 
             = (1 + Tan 2A) (Tan 2A) / ( 1 + Tan 2A)
 
              = Tan 2 A 
 
Answer  : Option (D) 
 
Thank You
 
 
one month ago
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