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```
For any triangle ABC prove that Sin B-C/2=B-C/A cos A/

```
3 years ago

Arun
25311 Points
```							Let a/sin A = b/sin B = c/sinC = kThen, a = k sinA, b = k sinB, c = k sinCRHSb-c/a cos A/2= (ksinB - ksinC/k sinA )cos A/2= {[2 cos B+C/2 Sin B-C/2]/ Sin A} cos A/2=[2* Sin B-C/2 cos (pi/2-A/2) .cos A/2] / sinA= [SinA* sinB-C/2] / sinA= Sin B-C/2= LHSHence proved
```
3 years ago
Rishi Sharma
614 Points
```							Dear Student,Please find below the solution to your problem.Let a/sin A = b/sin B = c/sinC = kThen,a = k sinA, b = k sinB, c = k sinCRHSb-c/a cos A/2= (ksinB - ksinC/k sinA )cos A/2= {[2 cos B+C/2 Sin B-C/2]/ Sin A} cos A/2=[2* Sin B-C/2 cos (pi/2-A/2) .cos A/2] / sinA= [SinA* sinB-C/2] / sinA= Sin B-C/2= LHSHence provedThanks and Regards
```
4 months ago
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### Course Features

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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions