Cos2A + cos2B + cos2 c +cos 2 (A+B+C) = 4 Cos (B+C) Cos (C+A) cos (A+B)

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Ravi malvia · Answer

2Cos(A+B)Cos(A-B)+Cos2C+Cos2(A+B+C)2Cos(A+B)Cos(A-B)+2Cos(2C+B+A)Cos(A+B)2Cos(A+B)[Cos(A-B)+Cos(2C+B+A)]2Cos(A+B)2Cos[(A-B+2C+B+A)/2]Cos[(A-B-2C-B-A)/2]4Cos(A+B)Cos(B+C)Cos(A+C)

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Cos2A + cos2B + cos2 c +cos 2 (A+B+C) = 4 Cos (B+C) Cos (C+A) cos (A+B)

Cos2A + cos2B + cos2 c +cos 2 (A+B+C) = 4 Cos (B+C) Cos (C+A) cos (A+B)

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