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sin2A+sin2B+sin2C=4cosA.cosB.sinC

Manish Tiwari , 11 Years ago
Grade 6
anser 1 Answers
purva

Last Activity: 11 Years ago

Use A+B+C=Pi Then use sin2A+sin2B=2sin(A+B)cos(A-B) by this I m gettin the final ans =4sinAsinBsinC

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