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sin2A+sin2B+sin2C=4cosA.cosB.sinC

sin2A+sin2B+sin2C=4cosA.cosB.sinC

Grade:6

1 Answers

purva
33 Points
8 years ago
Use A+B+C=Pi Then use sin2A+sin2B=2sin(A+B)cos(A-B) by this I m gettin the final ans =4sinAsinBsinC

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