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question mark

The maximum value of 5 cosx + 3cos(x + 60) + 3 is

a) 5

b) 11

c) 10

d) -1

pranshu aggarwal , 14 Years ago
Grade
anser 2 Answers
vikas askiitian expert

5cosx + 3cosx+60 + 3

5cosx + 3[cosxcos60 - sinxsin60] + 3

5cosx + 3[cosx/2 - (root3/2)sinx] + 3

(13/2)cosx - (3root3/2)sinx + 3

 

let 13/2 = a & 3root3/2 = b then

expression becomes

acosx - bsinx + 3

maximum value of this type of expression is equal to

[a2+b2]1/2+3 = maximum value

 

after plugging values of a,b we get

491/2+3 = max value

 10 = max value

 -4 = minimum value

 

option c) is correct

ApprovedApproved
Last Activity: 14 Years ago
ankit singh

Explanation:

5cosα+3cos(α+π3)+3

=5cosα+3(cosαcos(π3)sinαsin(π3))+3

=132cosα323sinα+3

#= sqrt( (13/2)^2+ (3/2sqrt3)^2) (cos alpha cos beta - sin alpha

sin beta ) + 3#

=7cos(α+β)+3,β=arccos(1314)

As cosine value [1,1], the maximum of the given function

=max7[1,1]+3=7+3=10

graph{(5 cos x + 3 cos ( x + pi/3 ) +3 - y )(y-10+0x)= 0[-10 10

Last Activity: 5 Years ago
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