heres the question
the sum to n terms of the series
(cos3x)/(sin2x)(sin4x) + (cos5x)/(sin4x)(sin6x) + (cos7x)/(sin6x)(sin8x)....is
plz tell the steps to solve such a problem
answer works out to be
1/2sinx{cosec2x - cosec(2n+2)x}
thnx in advance..:-)
heres the question
the sum to n terms of the series
(cos3x)/(sin2x)(sin4x) + (cos5x)/(sin4x)(sin6x) + (cos7x)/(sin6x)(sin8x)....is
plz tell the steps to solve such a problem
answer works out to be
1/2sinx{cosec2x - cosec(2n+2)x}
thnx in advance..:-)
arpan chandrashekhar , 14 Years ago
Grade
