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If the mediam of a triangle ABC through Ais perpendicular to AB, prove that tan A + TAN B =0????
dear student, we can prove tanA + 2tanB = 0.Let AD be the median through A=> AB = BDcosBApplying sine rule to ΔABC,AB/sinC = BC/sinA=> BDcosB/sinC = 2BD/sinA=> 2sinC - sinAcosB = 0=> 2sin(A+B) - sinAcosB = 0 ... [because C = π - (A+B)]=> 2sinAcosB + 2cosAsinB - sinAcosB = 0=> sinAcosB + 2cosAsinB = 0Dividing by cosAcosB,=> tanA + 2tanB = 0. BEST OF LUCK..!!!! We are all IITians and here to help you in your IIT JEE preparation. Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar : Click here to download the toolbar.. AMAN BANSAL
dear student,
we can prove tanA + 2tanB = 0.Let AD be the median through A=> AB = BDcosBApplying sine rule to ΔABC,AB/sinC = BC/sinA=> BDcosB/sinC = 2BD/sinA=> 2sinC - sinAcosB = 0=> 2sin(A+B) - sinAcosB = 0 ... [because C = π - (A+B)]=> 2sinAcosB + 2cosAsinB - sinAcosB = 0=> sinAcosB + 2cosAsinB = 0Dividing by cosAcosB,=> tanA + 2tanB = 0.
BEST OF LUCK..!!!!
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AMAN BANSAL
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